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An arrow is shot horizontally from the top of a building and it lands 200m from the foot of the building after 10 seconds. Assuming air resistance is negligeble, Calculate initial velocity and the height of the building

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Answer:

Explanation:

from 2nd equation of motion

S=vi t +1/2 a(t)²

vi=2 s-at /t

vi=2*200 m- 9.8*10 /10

vi=302/10

vi=30.2 m/s

H= vi*t+1/2 a t^2

H=30.2*10+1/2 9.8*10

H=302+1/2*9.8*10

H=302+1/2(98)

H=302+98/2

H=506/2

H=253

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