hihihi11138 hihihi11138

10-08-2020
Mathematics

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(x^2-4x)^2+7x^2-28x+12=0

Respuesta :

Ruilin0715 Ruilin0715

10-08-2020

Answer:

[tex]x^4-9x^2-28x=-12[/tex]

Step-by-step explanation:

[tex](x^2-4x)^2+7x^2-28x+12=0[/tex]

[tex](x^4-16x^2)+7x^2-28x=-12[/tex]

[tex]x^4-9x^2-28x=-12[/tex]

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