What is the area of triangle BCD to the nearest tenth of a square centimeter? Use special right triangles to
help find the height. Show your work.

What is the area of triangle BCD to the nearest tenth of a square centimeter Use special right triangles to help find the height Show your work class=

Respuesta :

Answer:

21.7 cm²

Step-by-step explanation:

Given:

Right ∆BCD,

<D = 60°

adjacent length = 5 cm

Required:

Area of ∆BCD

SOLUTION:

Step 1: find the height (opposite side length) of ∆BCD

[tex] tan(D) = \frac{opp}{adj} [/tex]

[tex] tan(60) = \frac{h}{5} [/tex]

Multiply both sides by 5

[tex] tan(60)*5 = \frac{h}{5}*5 [/tex]

[tex] tan(60)*5 = 8.7 cm [/tex] (approximated)

Step 2: find the area of ∆BCD

Area = ½*base*height

Area = ½*5*8.7 = 21.7 cm² (nearest tenth)

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