Step-by-step explanation:
A).
[tex] \frac{2}{ \sqrt{x} } [/tex]
Using the rules of indices
[tex] \sqrt{x} = {x}^{ \frac{1}{2} } [/tex]
So we have
[tex] \frac{2}{ {x}^{ \frac{1}{2} } } [/tex]
And also by the rules of indices
[tex] \frac{1}{ {a}^{b} } = {a}^{ - b} [/tex]
Applying the rules to the above expression we have the final answer as
[tex]2 {x}^{ - \frac{1}{2} } [/tex]
B).
[tex] \frac{3}{ {x}^{2} } [/tex]
By using the rules of indices
[tex] \frac{1}{ {a}^{b} } = {a}^{ - b} [/tex]
Applying the rules to the above expression
We have the final answer as
[tex]3 {x}^{ - 2} [/tex]
Hope this helps you
