Respuesta :
Answer:
New ratio ( white,blue and red) = 6:1:2
Step-by-step explanation:
Given:
Old ratio ( white,blue and red) = 8:3:2
Number of red balls = 10
Removed balls = 10 white , 10 blue
Find:
New ratio ( white,blue and red)
Computation:
Assume total number of balls = x
So,
Number of total balls = 2x / 13 = 10
Number of total balls = 65
Number of white balls = 40
Number of blue balls = 15
So,
Number of new white balls = 40 - 10 = 30
Number of new blue balls = 15 - 10 = 5
New ratio ( white,blue and red) = 30 : 5 : 10
New ratio ( white,blue and red) = 6:1:2
The new ratio of the white, blue, and red balls is 6:1:2.
Given to us
- A bag contains white,blue, and red balls ratio8:3:2 and there are 10 red balls,
- if 10 white balls and 10 blue balls are removed from the bag
Part 1
The balls in the bag are in the ratio 8:3:2, therefore, the balls in the bags are,
white balls = 8x
blue balls = 3x
red balls = 2x =10,
Solving for red balls,
[tex]2x = 10\\x =\dfrac{10}{2}\\x = 5[/tex]
Now, substituting the value of x to know the numbers of balls are,
white balls = 8x
[tex]= 8 \times 5\\=40[/tex]
blue balls = 3x
[tex]= 3\times 5\\=15[/tex]
Part 2
After removing, 10 white balls and 10 blue balls from the bag,
red balls = 10 balls
white balls = 40 balls - 10 balls = 30 balls
blue balls = 15 balls - 10 balls = 5 balls
Dividing all the number of balls by 5,
red balls = 10 balls
[tex]\dfrac{10\ balls}{5} = 2[/tex]
white balls = 30 balls
[tex]\dfrac{30\ balls}{5} = 6[/tex]
blue balls = 5 balls
[tex]\dfrac{5\ balls}{5} = 1[/tex]
Hence, the new ratio of the white, blue, and red balls is 6:1:2.
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