Respuesta :
Answer:
8
Step-by-step explanation:
Math Word Problem: Twice one number added to another number is 18. Four times the first number minus the other number is 12. Find the number.?
Let the two numbers be x and y
As per statement twice one number added to another number is 18.
2x + y = 18
y = 18 - 2x…Eq..1
Four times the first number minus the other number is 12.
4x - y = 12…Eq..2
Now substituting the value of y from Eq..1 to Eq..2
4x - y = 12
4x - (18 - 2x) = 12
4x - 18 + 2x = 12
4x + 2x = 12 + 18
6x = 30
x = 30 / 6
x = 5
Thus one number is 5. Now calculating the other number by putting the value of x in Eq. 1
y = 18 - 2x
y = 18 - 2×5
y = 18 - 10
y = 8
Other number is 8
Answer the two numbers are 5 and 8
Let us check the correctness of answer by putting the value of x and y in Eq. 1
y = 18 - 2x
8 = 18 - 2 × 5
8 = 18 - 10
8 = 8
Means answer is correct
2x + y = 18
y = 4x - 12
2x + y = 18
2x + (4x - 12) = 18
6x - 12 = 18
6x = 30
x = 5
y = 4x - 12
y = 4(5) - 12
y = 20 - 12
y = 8
Therefore the first number is 5 and the second number is 8.
y = 4x - 12
2x + y = 18
2x + (4x - 12) = 18
6x - 12 = 18
6x = 30
x = 5
y = 4x - 12
y = 4(5) - 12
y = 20 - 12
y = 8
Therefore the first number is 5 and the second number is 8.