Answer:
The point (-2, 4) is not a solution of the linear equation, 5·y = 3·x + 18
Please find attached the required graph of the linear equation 5·y = 3·x + 18 written in the form y = 3/5·x + 18/5
Step-by-step explanation:
The given equation is 5·y = 3·x + 18, from which we have;
y = 3/5·x + 18/5
To draw the graph, we generate for vales of y corresponding to values of x as follows;
x, y
-6, 0
-5, 0.6
-4, 1.2
-3, 1.8
-2, 2.4
-1, 3
0, 3.6
1, 4.2
2, 4.8
3, 5.4
4, 6
5, 6.6
6, 7.2
7, 7.8
8, 8.4
9, 9
10, 9.6
11, 10.2
12, 10.8
13, 11.4
14, 12
15, 12.6
16, 13.2
Therefore, when y = 0, x = -6, when x = 0, y = 3.6, when x = -2, y = 2.4, when y = 4, x = -2, x = 6
Therefore, the point (-2, 4) is not a solution of the linear equation, 5·y = 3·x + 18
