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85 POINTS! PLEASE HELP! Explain how to write an equation parallel to the equation y = 2x + 3 and the new line also includes the ordered pair (1,-2).

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ujalakhan18

Answer:

[tex]\huge\boxed{\sf y = 2x -4}[/tex]

Step-by-step explanation:

The given equation is:

y = 2x + 3

Where Slope = m = 2 , Y-intercept = b = 3

Parallel lines have equal slopes

So, Slope of new line = m = 2

Now, Finding y-intercept:

Given Point = (x,y) = (1,-2)

So, x = 1 , y = -2

Putting m, x and y in standard form of equation to get b:

[tex]\sf y = mx+b[/tex]

[tex]\sf -2 = (2)(1) + b\\-2 = 2 + b\\[/tex]

Subtracting 2 to both sides

[tex]\sf b = -2-2\\[/tex]

b = -4

So, the standard form og equation for the new line is :

[tex]\sf y = mx+b[/tex]

[tex]\sf y = 2x -4[/tex]

ricchad

Answer:

y = 2x - 4

Step-by-step explanation:

the problem is called (slope-intercept form)

the equation of the line is y = mx + b

the equation of a line is given as y = 2x + 3

slope = 2

b = y-intercept is where the line crosses the y-axis = 3

so point (x1, y1)  = (1, -2)

by using the equation.

y = mx + b

-2 = 2 (1) + b

-2 -2 = b

therefore b = -4

writing the new equation using the slope intercept form

y = mx + b  would be y = 2x + 4

so the equation parallel to the equation y = 2x + 3 is y = 2x - 4

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