Answer: (1, −5)
Step-by-step explanation:
Plot the given inequalities on coordinate plane.
For y < −3x + 3, plot y =−3x + 3
At x=0, y= 3
At y =0, 0=-3x+3
⇒ x= 1
so, plot points (0,3) and (1,0) and join to get y =−3x + 3, since inequality has '<' sign, so shade( in red) below line area and line should be dotted.
For y < x + 2, plot y = x + 2
At x=0, y= 2
At y =0, x=-2
so, plot points (0,2) and (-2,0) and join to get y = x + 2, since inequality has '<' sign, so shade( in orange) below line area and line should be dotted.
Now, plot all given points (1, −5) (1, 5) (5, 1) (−1, 5), we can clearly observe that (1, −5) lies in the solution set. (in common shaded region)
