Respuesta :

breadsticksandcheese

Answer:

0.15(5,-1)

Step-by-step explanation:

[tex]\frac{v_{1} * v_{2} }{|v_{2}|^{2} }*v_{2}[/tex]  ⇒ [tex]\frac{(2)(5)+(6)(-1)}{\sqrt{5^2+(-1)^2} }(5,-1)[/tex] ⇒  [tex]\frac{4}{26} (5,-1)[/tex]  ⇒  [tex]0.15(5,-1)[/tex]

The best approximation of the projection  IS ( 5,-1).

What is the projection of a vector?

  • The sometimes-indicated vector projection of a vector an onto (or onto) a nonzero vector b The orthogonal projection of an onto a line parallel to b is referred to as (also known as the vector component or vector resolution of an in the direction of b).
  • Although the word "projection" has several different connotations, they all refer to sending something out or forward.
  • A projection is something that sticks out from a wall; it can be a movie; it can be an actress who speaks into a big auditorium without seeming shouty; or it can be something that is projected onto a screen.

Vector A ,

                 (2,6) in terms of vectors is represented by = 2 i +6 j

Vector B,

                 (5,-1) in terms of vectors is represented by =5 i - 1 j

Projection of Vector A on Vector B

       [tex]\frac{(A . B)(B)}{IBI^{2} } \\[/tex] =  [tex]\frac{[(2i + 6j).(5i - j)]( 5i - j)}{\sqrt{5^{2} }+ (-1)^{2} }[/tex]

[tex]= \frac{(2)(5) +(6)(-1)}{\sqrt{5^{2} }+(-1)^{2} }[/tex]

= ( 5 ,-1 ) ⇒ 0.15 (5,-1)

Therefore, The best approximation of the projection  IS ( 5,-1) .

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