Answer:
[tex]\frac{14}{55}[/tex]
Step-by-step explanation:
note that
n! = n(n - 1)(n - 2) .... × 3 × 2 × 1
Given
[tex]\frac{8!9!}{5!12!}[/tex]
Cancel the terms from 8! ( 5 × 4 × 3 × 2 × 1 ) with the same terms from
5! ( 5 × 4 × 3 × 2 × 1 ) leaving
8 × 7 × 6 = 336 on the numerator
Similarly
Cancel the terms from 9! and 12!
leaving 12 × 11 × 10 = 1320 on the denominator, thus simplifies to
[tex]\frac{336}{1320}[/tex]
= [tex]\frac{14}{55}[/tex]
