Answer:
The answer is
Step-by-step explanation:
To find the equation of the line using a point and slope we use the formula
where m is the slope
(x1 ,y1) is the given point
From the question
slope = 3/2
point = ( 2 , - 1)
Substitute these values into the above formula
That's
[tex]y + 1 = \frac{3}{2} (x - 2)[/tex]
[tex]y + 1 = \frac{3}{2} x - 3[/tex]
[tex]y = \frac{3}{2} x - 3 - 1[/tex]
We have the final answer as
[tex]y = \frac{3}{2} x - 4[/tex]
Hope this helps you
Answer:
y= 3/2x -4
Step-by-step explanation:
Since we are given a point and a slope, we can use the point-slope formula.
[tex]y-y_{1} = m(x-x_{1})[/tex]
where m is the slope and (x1, y1) is a point the line passes through.
We know the slope is 3/2 and the point we are given is (2, -1).
[tex]m=\frac{3}{2} \\\\x_{1} = 2\\\\y_{1} = -1[/tex]
Substitute the values into the formula.
[tex]y- -1 = \frac{3}{2} (x-2)[/tex]
[tex]y+1=\frac{3}{2} (x-2)[/tex]
We want to find the equation of line , which is y=mx+b ( m is the slope and b is the y-intercept). Therefore, we must get y by itself on the left side of the equation.
First, distribute the 3/2. Multiply each term inside the parentheses by 3/2.
[tex]y+1= (\frac{3}{2} * x) + (\frac{3}{2} *-2)[/tex]
[tex]y+1= \frac{3}{2}x + (\frac{3}{2} *-2)[/tex]
[tex]y+1=\frac{3}{2} x + -3[/tex]
[tex]y+1=\frac{3}{2} x -3[/tex]
Next, subtract 1 from both sides.
[tex]y+1-1=\frac{3}{2} x + -3 -1[/tex]
[tex]y=\frac{3}{2} x + -3 -1[/tex]
[tex]y=\frac{3}{2} x -4[/tex]
Now the line is in slope intercept form, therefore the equation of the line is y=3/2x -4. The slope of the line is 3/2 and the y-intercept is -4.
