Respuesta :
Answer:
v(m) = 8 + 48m+ 180m² +216m³
Step-by-step explanation:
Let's first of all represent the edge of the the cube as a function of minutes.
Initially the egde= 2feet
As times elapsed , it increases at the rate of 6 feet per min, that is, for every minute ,there is a 6 feet increase.
Let the the egde be x
X = 2 + 6(m)
Where m represent the minutes elapsed.
So we Al know that the volume of an edge = edge³
but egde = x
V(m) = x³
but x= 2+6(m)
V(m) = (2+6m)³
v(m) = 8 + 48m+ 180m² +216m³
The volume of cube as function of m is, [tex]V(m)=72m[/tex]
Let us consider that edge of cube is a feet.
Since, The edge is increasing at the rate of 6 feet per minute.
[tex]\frac{da}{dt}=6feet/min.[/tex]
Volume of cube , V = [tex]a^{3}[/tex]
[tex]\frac{dV}{dt} =3a^{2} \frac{da}{dt}[/tex]
Substituting the value of da/dt in above equation.
We get, [tex]\frac{dV}{dt}=3a^{2}*(6) =18a^{2} \\\\dV=18a^{2}dt[/tex]
Integrating on both side.
[tex]V=18a^{2}t[/tex]
Since, number of minutes elapsed is m.
Substitute , t = m and a = 2 feet in above equation.
We get, [tex]V=18(2)^{2}*m=72m[/tex]
Thus, the volume of cube as function of m is, [tex]V(m)=72m[/tex]
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