Answer:
x=1 or x=3
Step-by-step explanation:
Hello, please consider the following.
[tex]x^2-4x+3=0\\\\\text{Step 1 - complete the square}\\\\x^2-4x+3=x^2-2*2*x+3=(x-2)^2-4+3=(x-2)^2-1=0\\\\\text{Step 2 - move the constant to the right side, meaning adding 1 here.}\\\\(x-2)^2=1\\\\\text{Step 3 - take the root}\\\\x-2=\pm1\\\\x=2-1=1 \ \ or \ \ x=2+1=3[/tex]
Thank you
