Answer:
Step-by-step explanation:
Given the expression cos(3x-π) = -√3/2, we are to find the values of x that represent the solutions to the equation.
cos(3x-π) = -√3/2
take inverse cos of both sides
cos⁻¹[cos(3x-π)] = cos⁻¹[-√3/2]
3x-π = cos⁻¹[-√3/2]
3x-π = -30°
since 180° = π rad
Hence;
3x- 180° = -30°
3x = -30°+ 180°
3x = 150°
x = 150°/3
x = 50°
Since cos is negative in the first second and 3rd quadrant;
3x-180° = -30°
In the second quadrant;
3x-180° = 180-30
3x - 180 = 150
3x = 150+180
3x = 330
x = 110°
In the third quadrant;
3x-180° = 270+30
3x - 180 = 300
3x = 300+180
3x = 480
x = 480/3
x = 160
