Answer:
10:5 OR 2:1
Step-by-step explanation:
Let x be the parts of 25% dextrose and
y be the parts of 10% dextrose are mixed so that
20% dextrose mixture is obtained.
amount of dextrose in the mixture will be 20% of (x+y).
We have to find the value of [tex]\frac{x}y \ OR\ x:y[/tex]
Now, we can apply the concept that sum of amount of dextrose in the two liquids will be equal to the amount of dextrose in the mixture.
[tex]\Rightarrow x \times 25\% + y \times 10\%=(x+y)\times 20\%\\\Rightarrow x \times\dfrac{25}{100} + y \times \dfrac{10}{100}=(x+y)\times \dfrac{20}{100}\\\Rightarrow x \times25 + y \times 10=(x+y)\times 20\\\Rightarrow 25x + 10y=20x+20y\\\Rightarrow 25x -20x =20y-10y\\\Rightarrow 5x=10y\\\Rightarrow \dfrac{x}{y} = \dfrac{10}{5}\\\Rightarrow \bold{x:y=10:5\ OR\ 2:1}[/tex]
So, the answer is 10:5 or 2:1.
Answer:
4.90% is approximately the new Dextrose concentration.
Explanation:
Volume by Volume percent is given by ;
Volume percentage of dextrose solution = 5%
In 100 mL of solution 5 ml of dextrose is present.
Now, volume sterile water added was equal to the 40% of volume of dextrose volume.
So, volume of the sterile water added =
Total volume of the solution after addition of water = 100 mL + 1 mL = 102 mL
New concentration of dextrose will be;
4.90% is approximately the new Dextrose concentration.
Step-by-step explanation:
