Answer:
The correct option is;
C. -3, multiplicity 2; -1, multiplicity 1; 1, multiplicity 1
Please find attached the required function graph
Step-by-step explanation:
To solve the equation f(x) = 2·x⁴ + 12·x³ + 16·x² -12·x - 18, by graphing the function, we have;
x [tex]{}[/tex] F(x)
-4[tex]{}[/tex] 30
-3[tex]{}[/tex] 0
-2[tex]{}[/tex] 6
-1[tex]{}[/tex] 0
0 [tex]{}[/tex] -18
1[tex]{}[/tex] 0
2[tex]{}[/tex] 150
The shape of a graph with multiplicity of 2
Given that the graph bounces of the horizontal axis at the y-intercept at point x = -3, the factor (x - 3) must be a quadratic of the form (x - 3)², thereby having a multiplicity of 2 in the solution which are;
x = 1, -1, and, giving
(x - 1)·(x + 1)·(x - 3)² = 0
Therefore, the correct option is -3, multiplicity 2; -1, multiplicity 1; 1 multiplicity 1.
