nastassjamotro nastassjamotro

10-09-2016
Mathematics

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find the slope of f(x)=x^3-2x^2-1 at the point (2,-1). then write the equation of the tangent line at the point (2,-1). show all work

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10-09-2016

Hello,

[tex]y=x^3-2x^2-1\\ y'=3x^2-4x\ if\ x=2\ then\ y'=3*2^2-4*2=12-8=4\\ The \ equation \ is \ : y+1=4(x-2)\\ y=4x-9 [/tex]

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