Al+3is the third electron ionization level of the atom Al.
Al has an atomic number of 13, thus it has 13 protons and electrons.
By shooting a photon with a certain amount of energy (the energy in kj/mol) the atom will be ionized and lose the electrons.
13-3 = 10
The total amount of electrons in Al3+ is 10 *The energy required to ''detach'' 3 electrons from the 3s and 3p orbital.
