Find three consecutive odd integers such as the sum of the smallest number and middle number is 27 less than 3 times the largest number

Respuesta :

Answer:

           17, 19 and 21

Step-by-step explanation:

x    - an integer

then: 2x is an even number and 2x+1 is an odd number

consecutive odd numbers increase by 2  (even numbers too)

so the next odd number (the middle number) is:

2x+1+2 = 2x+3

and the third (the largest) consecutive is:

2x+3+2 = 2x+5

the sum of the smallest and the middle numbers is:

2x + 1 + 2x + 3

3 times the largest number is:  

3(2x + 5)  

the sum of the smallest number and middle number is 27 less than 3 times the largest number, so:

2x + 1 + 2x + 3 = 3(2x + 5) - 27

4x + 4 = 6x + 15 - 27

    -6x       -6x

-2x + 4 = -12

    -4       -4

 -2x  = -16

 ÷(-2)    ÷(-2)

   x = 8

2x+1 = 2•8+1 = 17

2x+3 = 2•8+3 = 19

2x+5 = 2•8+5 = 21

Check:

2x+1+2x+3 = 16+1+16+3 = 36

36+27 = 63

63:3 = 21 = 2x+5