Given :
Radius of uranium atom , [tex]R=149\ pm = 149\times 10^{-12}\ m[/tex] .
To Find :
How many uranium atoms would have to be laid side by side to span a distance of 1.66 mm .
Solution :
Diameter of uranium atom :
[tex]D=2r=2\times 149\times 10^{-12}\ m\\\\D=298\times 10^{-12}\ m[/tex]
Number of atoms are :
[tex]n=\dfrac{D}{d}\\\\n=\dfrac{1.66\times 10^{-3}\ m}{ 298\times 10^{-12}\ m}\\\\n=5.57\times 10^{6}[/tex]
Hence , this is the required solution .
