Respuesta :
The division 4+2i/8-3i is performed by multiplying the numerator and denominator by (8+3i).
Given
The division 4+2i/8-3i is performed by multiplying the numerator and denominator by
Expression; [tex]\rm \dfrac{4+2i}{8-3i}[/tex]
A complex conjugate is formed by changing the sign between two terms in a complex number i.e. a+ ib has conjugate a-ib and a- ib has conjugate like a+ ib.
The division 4+2i/8-3i is performed by multiplying the numerator and denominator by (8+3i).
[tex]=\rm \dfrac{4+2i}{8-3i}\\\\= \rm \dfrac{4+2i}{8-3i}\times \dfrac{8+3i}{8+3i}\\\\= \dfrac{(4+2i) \times (8+3i)}{(8)^2-(-3i)^2}\\\\= \dfrac{32+12i+16i+6i^2}{64+9}\\\\=\dfrac{32+28i+6i^2}{73}[/tex]
Hence, The division 4+2i/8-3i is performed by multiplying the numerator and denominator by (8+3i).
To know more about Division click the link given below.
https://brainly.com/question/10628378
