Answer:
[tex]15molH[/tex]
Explanation:
Hello,
In this case, given that one mole of glucose, contains six moles of oxygen (subscript), we can also see it contains twelve moles of hydrogen (subscript), therefore, the moles of hydrogen in the sample are computed by:
[tex]0.75molO*\frac{1molC_6H_{12}O_6}{6molO}*\frac{12molH}{1molC_6H_{12}O_6}\\ \\=1.5molH[/tex]
Best regards.