Answer:
the width of the path is 2.81 m
Step-by-step explanation:
given:
A circular plot of diameter 28m is surrounded by a path of uniform width
If the area of the path is 346.5^2
find:
the width of the path.
---------------------------------
dia of circle = 28m
let Si = side of inner square path = 28 m
let So = outer side of square path = ?
1st step
is to get the total area
At = area of path + area of inner square
At = 346.5 + (28 x 28)
At = 1130 m²
2nd step
get the outer side of square path So
At = So²
1130 = So²
So = √1130
So = 33.62 m
lastly solve the width of path:
Width (w) = (So - Si)/2
w = (33.62 m - 28 m) / 2
w = 2.81 m
therefore,
the width of the path is 2.81 m
