Answer:
[tex]x=5,y=4[/tex]
Step-by-step explanation:
[tex]2x-3y=-2[/tex]
Add 3y to both sides:
[tex]2x-3y+3y=-2+3y[/tex]
[tex]2x=-2+3y[/tex]
Divide both sides by 2:
[tex]\frac{2x}{2}=-\frac{2+3y}{2}[/tex]
[tex]x=\frac{-2+3y}{2}[/tex]
Substitute this into the second equation:
[tex]4* \frac{-2+3y}{2}+y=24[/tex]
[tex]2\left(3y-2\right)+y=24[/tex]
[tex]7y-4=24[/tex]
Add 4 to both sides:
[tex]7y-4+4=24+4[/tex]
[tex]7y=28[/tex]
Divide both sides by 7:
[tex]\frac{7y}{7}=\frac{28}{7}[/tex]
[tex]y=4[/tex]
We know that [tex]x=\frac{-2+3y}{2}[/tex]
Thus, [tex]x=\frac{-2+3* \:4}{2}[/tex]
[tex]x=\frac{10}{2}[/tex]
[tex]x=5[/tex]
Answer:
using elimination rule
multiply equation 2 by 3
we get, 12x+3y=72
now solve both equation
2x-3y= -2
(+)12x+3y=72
-----------------
14x=70
x=70/14=5
put value of x in any of the equation y=4
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