Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{15y + 6}}}}}[/tex]
Step-by-step explanation:
[tex] \sf{(8y + {y}^{2} + 7y + 9) - ( {y}^{2} + 3)}[/tex]
When there is a ( - ) in front of an expression in parentheses, change the sign of each term
[tex] \dashrightarrow \sf{8y + {y}^{2} + 7y + 9 - {y}^{2} - 3}[/tex]
Since two opposites add up to zero, remove them from the expression
[tex] \dashrightarrow{ \sf{8y + 7y + 9 - 3}}[/tex]
Add the like terms : 8y and 7y
[tex] \dashrightarrow{ \sf{15y + 9 - 3}}[/tex]
The negative and positive integers are always subtracted but posses the sign of the bigger integer
[tex] \longrightarrow{ \sf{15y + 6}}[/tex]
Hope I helped!
Best regards! :D
