Answer:
1. [tex]\frac{10}{21}[/tex]
2. [tex]\frac{405}{49} = 8\frac{13}{49}[/tex]
Step-by-step explanation:
first one:
[tex]p^{2} q[/tex] = [tex](\frac{1}{3})^{2}[/tex] × [tex]4\frac{2}{7}[/tex] = [tex]\frac{1}{9}[/tex] × [tex]\frac{30}{7}[/tex] = [tex]\frac{1}{3}[/tex] × [tex]\frac{10}{7}[/tex] = [tex]\frac{10}{21}[/tex]
second one:
[tex]t^{2}[/tex]/[tex]s[/tex] = [tex](1\frac{2}{7})^{2}[/tex] / [tex]\frac{1}{5}[/tex] = [tex](\frac{9}{7})^{2}[/tex] × [tex]5[/tex] = [tex]\frac{81}{49}[/tex] × [tex]5[/tex] = [tex]\frac{405}{49}[/tex] = [tex]8\frac{13}{49}[/tex]
