Answer:
175 m
Explanation:
The average velocity for constant acceleration is the average of the beginning and ending velocities. That is (0+39)/2=19.5 m/s. If the bicyclist rides for 9 seconds, the distance traveled is ...
(9 s)(19.5 m/s) = 175.5 m
She would travel 175.5 meters in that time.
The distance traveled by the bicyclist at the same time period is 175.5 m.
Your question not complete, i believe it is missing this additional information below:
"Seven bicyclist are racing. Each bicyclist rides for 9s, If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time?"
The given parameter:
initial velocity of the bicyclist, u = 0
final velocity of the bicyclist, v = 39 m/s
time of motion of the each bicyclist, t = 9s
To find:
Let the distance traveled by the bicyclist = s
The distance traveled by the bicyclist at the same time period is calculated as;
[tex]s = (\frac{u+v}{2} )t\\\\s = (\frac{0 + 39}{2} ) \times 9\\\\s = 19.5 \times 9\\\\s = 175.5 \ m[/tex]
Thus, the distance traveled by the bicyclist at the same time period is 175.5 m.
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