Answer:
Since BD bisects Angle ABC, Angle ABD = Angle DBC
[tex]3x+6=7x-18[/tex]
Subtract 6 from both sides:
[tex]3x+6-6=7x-18-6[/tex]
[tex]3x=7x-24[/tex]
Subtract 7x from both sides:
[tex]3x-7x=7x-24-7x[/tex]
[tex]-4x=-24[/tex]
Divide both sides by -4:
[tex]\frac{-4x}{-4}=\frac{-24}{-4}[/tex]
[tex]x=6[/tex]
Angle [tex]ABD=3x+6=3(6)+6=18+6=24[/tex]
Angle [tex]CBD=7x-18=7(6)-18=42-18=24[/tex]
Angle [tex]ABC=ABD+CBD=24+24=48[/tex]
