Given :
2.5 mole of Sulfuric acid [tex]( H_2SO_4 )[/tex] .
To Find :
Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid
Solution :
Let us assume volume of water be 1 L .
Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .
So , for 2.5 mole sulfuric acid required 5 mole of NaOH .
Moles of NaOH ,
[tex]n=M\times Volume \\\\n=5\times 1=5\ moles[/tex]
Molecular mass of NaOH , M.M = 58.44 g/mol .
Mass of 5 moles of NaOH :
[tex]m=5\times 58.44\ g\\\\m=292.2\ g[/tex]
Hence , this is the required solution .
