Respuesta :
Answer and Step-by-step explanation:
Given: diameter = 16ft height = 5 ft. Depth = 4ft
Work =?
As we know that work = force x distance
W= distance x density x volume
W= ʃ04 (5-y) 62.5x ∏ (d/2)2dy (area = ∏r2 , r= d/2)
= 62.5 ʃ04 (5-y) ∏ (4y) dy
=62.5∏ ʃ04 (5-y) 4ydy
=62.5∏ ʃ04 20y-4y2dy
=62.5∏ |20y2/2 – 4y3/3|04
=62.5∏ |74.66|
=14659ft.lbs (approximately)
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The work (in ft-lb) that would be required to pump all of the water over the upper rim is :
Given:
- Diameter = 16ft Height = 5 ft. Depth = 4ft
Work =?
Formula:
work = force x distance
W= distance x density x volume
W= ʃ04 (5-y) 62.5x ∏ (d/2)2dy (area = ∏r2 , r= d/2)
W = 62.5 ʃ04 (5-y) ∏ (4y) dy
W =62.5∏ ʃ04 (5-y) 4ydy
W =62.5∏ ʃ04 20y-4y2dy
W =62.5∏ |20y2/2 – 4y3/3|04
W =62.5∏ |74.66|
W =14659ft.lbs (approximately)
The work (in ft-lb) that would be required to pump all of the water over the upper rim is 14659ft.lbs
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