Part A
What is the magnitude of the momentum of a 0.0073-kg marble whose speed is 0.65 m/s?
Express your answer to two significant figures and include appropriate units.
Part B
What is the speed of a 0.136-kg baseball whose momentum has a magnitude of 3.14 kg⋅m/s?
Express your answer to two significant figures and include appropriate units.

Respuesta :

Answer:

(A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s

Explanation:

Given that,

Mass of marble = 0.0073 kg

Speed = 0.65 m/s

(A). We need to calculate the magnitude of the momentum of the marble

Using formula of momentum

[tex]p = mv[/tex]

Where, m = mass

v = velocity

Put the value into the formula

[tex]p=0.0073\times0.65[/tex]

[tex]p=0.004745\ kg m/s[/tex]

(B). Mass of baseball = 0.136 kg

Momentum of baseball = 3.14 kg m/s

We need to calculate the speed of baseball

Using formula of momentum

[tex]p=mv[/tex]

[tex]v=\dfrac{p}{m}[/tex]

Put the value into the formula

[tex]v=\dfrac{3.14}{0.136}[/tex]

[tex]v=23.0\ m/s[/tex]

Hence, (A). The magnitude of the momentum of the marble is 0.004745 kg m/s.

(B). The speed of baseball is 23.0 m/s