Answer:
The freezing point is -3.72 degrees Celsius
Explanation:
In this question, by assuming the complete dissociation of the salt, we want to calculate the freezing point of an aqueous 1 M NaCl solution .
We proceed as follows;
Firstly, we write the dissociation equation;
NaCl ——> Na+ + Cl-
So the number of ions present in the dissociation is 2. This means that the Vant Hogg factor also called I = 2
Mathematically;
ΔTf = Kf*m*i
m represents the molality which is given as 1
So by substituting the values, we have;
ΔTf = 1.86 * 1 * 2 = 3.72 degrees Celcius
The freezing point however is 0 - ΔTf = 0 - 3.72 = -3.72 degrees Celcius
