Write balanced molecular and net ionic equations for the following metathesis (double displacement) reactions, if they occur. If no reaction occurs, write NR on the product side. All reactants are aqueous. Phase subscripts must be included to indicate what products stay in solution (aq), and what products precipitate (s).
a. zinc acetate + sodium carbonate
b. barium nitrate + sodium sulfate
c. lead (II) nitrate + sodium sulfate
d. zinc acetate + sodium sulfate
e. barium nitrate+ potassium iodide
f. lead (I) nitrate+ potassium iodide
g. zinc acetate + potassium iodide

Respuesta :

Answer:

attached below is the required solution

Explanation:

A) Zinc acetate + Sodium carbonate

B) barium nitrate + sodium sulfate

C ) lead ( II ) nitrate + sodium sulfate

D) Zinc acetate + sodium sulfate

E) barium nitrate + potassium iodide

F) Lead ( I ) nitrate + potassium iodide

G) Zinc acetate + potassium iodide

Ver imagen batolisis

A net ionic equation shows the ions that underwent change in a reaction hence it excludes the spectator ions.

A metathesis reaction is one which the cations exchange anion partners in the products. A general example of a methathesis reaction is AX + BY ---> AY + BX.

The molecular and net ionic equation for the reactions are;

1) Zn(CH3COO)2(aq) + Na2CO3(aq) -----> ZnCO3(s) + 2CH3COONa(aq)

Net ionic equation; Zn^2+(aq) + CO3^2-(aq) ------>  ZnCO3(s)

2) Ba(NO3)2(aq) + Na2SO4(aq) ------> BaSO4(s) + 2NaNO3(aq)

Net ionic equation; Ba^2+(aq) + SO4^2-(aq) ------> BaSO4(s)

3) Pb(NO3)2(aq) +  Na2SO4(aq) ------> PbSO4(s) + 2NaNO3(aq)

Net ionic equation; Pb^2+(aq) + SO4^2-(aq) ------> PbSO4(s)

4) Zn(CH3COO)2(aq) + Na2SO4(aq) ------> ZnSO4(s) + 2CH3COONa(aq)

Net ionic equation: Zn^2+(aq) + SO4^2-(aq) ------>  ZnSO4(s)

5) Ba(NO3)2(aq) + 2KI(aq)  ------> 2KNO3(aq) + BaI2(aq)

There is no net ionic equation for this reaction.

6) Pb(NO3)2(aq) + 2KI(aq)  -------> PbI2(s) + 2NaNO3(aq)

Net ionic equation: Pb^2+(aq) + 2I^-(aq) ----->  PbI2(s)

7) Zn(CH3COO)2(aq) + 2KI(aq) -----> ZnI2(aq) + 2CH3COOK(aq)

There is no net ionic equation for this reaction

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