Answer:
40%
Step-by-step explanation:
10 minutes late would mean 18 minutes late on the graph. The graph goes from 10-30 which creates a difference of 20. 8 divided by 20 equals 40 percent.
40 percent of the time does Oliver arrives within 10 minutes of John's arrival time.
Given that,
Oliver is typically 10–30 minutes late for his shift at work.
The distribution for the minutes he is late forms a consistent pattern, which can be graphed as the given uniform density curve.
John and Oliver are working a shift that starts at the same time. John always arrives 8 minutes late.
We have to determine,
What percentage of the time does Oliver arrive within 10 minutes of John's arrival time?
According to the question,
Oliver is typically 10–30 minutes late for his shift at work.
John and Oliver are working a shift that starts at the same time.
John always arrives 8 minutes late.
From the complete information, the probability distribution will be:
[tex]= \dfrac{1}{b-a}\\\\= \dfrac{1}{30-10}\\\\= \dfrac{1}{20}[/tex]
Here, John always arrives 8 minutes late.
Therefore,
The percentage of the time that Oliver arrives within 10 minutes of John's arrival time is,
[tex]\rm = 8 \times \dfrac{1}{20}\\\\= \dfrac{2}{5}\\\\= 0.4 \times 100 \\\\= 40 \ Percent[/tex]
Hence, 40 percent of the time does Oliver arrives within 10 minutes of John's arrival time.
For more details refer to the link given below.
https://brainly.com/question/9329013
