6. An alloy of iron contains 75.0% iron and 25.0% other elements. How many grams of iron are present in 150. g of the alloy?

Respuesta :

Answer:

108.5

Explanation:

half of 150 is 75 and half of that is 32.5. Add that to 75 and you'll get your answer

112.5 g of iron is present in the alloy.

From the question given above, the following data were obtained:

Percentage of iron (Fe) = 75%

Percentage of other elements = 25%

Mass of the alloy = 150 g

Mass of iron (Fe) =?

The mass of the iron present in the alloy can be obtained as follow:

[tex]Percentage = \frac{mass of element }{total mass }\\\\[/tex]

75% = [tex]\frac{mass of Fe}{150}[/tex]

[tex]0.75 = \frac{mass of Fe}{150}\\\\[/tex]

Cross multiply

Mass of Fe = 0.75 × 150

Mass of Fe = 112.5 g

Therefore, 112.5 g of iron is present in the alloy.

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