Respuesta :
Answer:
108.5
Explanation:
half of 150 is 75 and half of that is 32.5. Add that to 75 and you'll get your answer
112.5 g of iron is present in the alloy.
From the question given above, the following data were obtained:
Percentage of iron (Fe) = 75%
Percentage of other elements = 25%
Mass of the alloy = 150 g
Mass of iron (Fe) =?
The mass of the iron present in the alloy can be obtained as follow:
[tex]Percentage = \frac{mass of element }{total mass }\\\\[/tex]
75% = [tex]\frac{mass of Fe}{150}[/tex]
[tex]0.75 = \frac{mass of Fe}{150}\\\\[/tex]
Cross multiply
Mass of Fe = 0.75 × 150
Mass of Fe = 112.5 g
Therefore, 112.5 g of iron is present in the alloy.
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