The equation [tex]x^{3} - 3[/tex] has x values as 0, [tex]\sqrt{3}[/tex] and -[tex]\sqrt{3}[/tex].
We are given,
3 is subtracted from the cube of a number.
Let the number be x then we can write it as:
[tex]x^{3}[/tex] - 3
We are to solve for x.
We can write the equation as:
[tex]x^{3}[/tex] - 3 = 0
x ( [tex]x^{2}[/tex]- 3 ) = 0
x = 0 and ( [tex]x^{2}[/tex] - 3 ) = 0
x = 0 and [tex]x^{2}[/tex] = 3
x = 0 and x = ±[tex]\sqrt{3}[/tex]
So we have,
x = 0, [tex]\sqrt{3}[/tex] and -[tex]\sqrt{3}[/tex]
Thus we have x values as 0, [tex]\sqrt{3}[/tex] and -[tex]\sqrt{3}[/tex].
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