Answer:
a can be anything. There are infinite solutions.
Step-by-step explanation:
[tex]4(a+2)=8+4a[/tex]
Expand:
[tex]4a+4\times\:2=8+4a[/tex]
[tex]4a+8=8+4a[/tex]
Subtract 8 from both sides:
[tex]4a+8-8=8+4a-8[/tex]
[tex]4a=4a[/tex]
Subtract 4a from both sides:
[tex]4a-4a=4a-4a[/tex]
[tex]0=0[/tex]
Since both sides are equal, a has infinite solutions as no matter what value it is, it will not affect the end result of [tex]0=0[/tex] which is true.