In 1979, zoologists estimated the number of fish in a local pond to be about
540. In 1989, 10 years later, the zoologists estimated that the number of
fish had increased to 990. Assuming that the fish population increased
linearly, how many fish lived in the pond in 1986? *
ann

In 10 years, we can tell that the amount of fish increased by 1.833...(990 divided by 540) times. If we divide 1.833... by 10, we can find how much the pond increases by yearly. we get 0.1833... If we multiply that by 7 (because the gap between 1986 and 1979 is 7 years), we get 1.2833... So, if we multiply 540 by 1.28333..., we get 693 fish.

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In 1979, zoologists estimated the number of fish in a local pond to be about 540. In 1989, 10 years later, the zoologists estimated that the number of fish had increased to 990. Assuming that the fish population increased linearly, how many fish lived in the pond in 1986? * ann

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In 1979, zoologists estimated the number of fish in a local pond to be about
540. In 1989, 10 years later, the zoologists estimated that the number of
fish had increased to 990. Assuming that the fish population increased
linearly, how many fish lived in the pond in 1986? *
ann