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I'VE ASKED THIS ONE EARLIER BUT NOBODY ANSWERED Point D is in the interior of \small \angle ABC, \small m\angle ABC=20x-15, \small m\angle ABD=6x-5, and \small m\angle DBC=x+16. What is \small m\angle ABD? \small m\angle ABD= degrees

IVE ASKED THIS ONE EARLIER BUT NOBODY ANSWERED Point D is in the interior of small angle ABC small mangle ABC20x15 small mangle ABD6x5 and small mangle DBCx16 W class=

Respuesta :

Hrishii

Answer:

7°

Step-by-step explanation:

Since, Point D is in the interior of angle ABC.

Therefore,

[tex]m\angle ABC = m\angle ABD + m\angle DBC\\

20x - 15 = 6x - 5 + x + 16\\

20x - 15 = 7x + 11\\

20x - 7x = 11+15\\

13x = 26 \\ x = \frac{26}{13} \\ x = 2 \\ \\ m\angle ABD = (6x - 5) \degree \\ m\angle ABD = (6 \times 2 - 5) \degree\\ m\angle ABD = (12 - 5) \degree \\ \huge \red{ \boxed{ m\angle ABD = 7\degree}}[/tex]

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