Air44
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[tex] \frac{3}{2} + \frac{2m}{9} = \frac{37}{18} [/tex]
How do I solve this and make it the most simplified it can be?​

Respuesta :

Stephen46

Answer:

[tex]m = \frac{5}{2} [/tex]

Step-by-step explanation:

[tex]\frac{3}{2} + \frac{2m}{9} = \frac{37}{18}[/tex]

Multiply through by 18 to eliminate the fraction

That's

[tex]18 \times \frac{3}{2} + 18 \times \frac{2m}{9} = 18 \times \frac{37}{18} \\ 27 + 4m = 37[/tex]

Subtract 27 from both sides

That's

[tex]27 - 27 + 4m = 37 - 27 \\ 4m = 10[/tex]

Divide both sides by 4

That's

[tex] \frac{4m}{4} = \frac{10}{4} [/tex]

We have the final answer as

[tex]m = \frac{5}{2} [/tex]

Hope this helps you

vikram991

➢ Answєr :

[tex]\Huge{\boxed{\sf{\red{m = \frac{5}{2}}}}}[/tex]

➢ Explαnαtion :

[tex]\displaystyle{\sf{ \frac{3}{2} + \frac{2m}{9} = \frac{37}{18}}} [/tex]

| ∵ Transposing 3/2 to R.H.S

[tex]\implies[/tex] [tex]\displaystyle{\sf{ \frac{2m}{9} = \frac{37}{18} - \frac{3}{2}}} [/tex]

[tex]\implies[/tex] [tex]\displaystyle{\sf{ \frac{2m}{9} = \frac{37-27}{18}}} [/tex]

[tex]\implies[/tex] [tex]\displaystyle{\sf{ \frac{2m}{9} = \frac{10}{18} = \frac{5}{9}}} [/tex]

[tex]\implies[/tex] [tex]\displaystyle{\sf{ 2m = \frac{5}{9} \times 9}} [/tex]

[tex]\implies[/tex] [tex]\displaystyle{\sf{ 2m = 5}} [/tex]

[tex]\longrightarrow[/tex] [tex]\large{\boxed{\sf{\red{ m = \frac{5}{2}}}}}[/tex]