Answer:
Q = 3937.56 J
Explanation:
Heat transferred due to change in temperature is given by :
[tex]Q=mc\Delta T[/tex]
c is the specific heat of water, c=4.18 J/g-°C
We have, m = 15 g, [tex]T_i=100^{\circ} C\ \text{and}\ T_f=37.2^{\circ} C[/tex]
So,
[tex]Q=15\times 4.18\times (37.2-100)\\Q=-3937.56\ J[/tex]
Hence, 3937.56 J of heat is transferred.