Answer:
Follows are the solution to this question:
Explanation:
The creation of four fragments,
(n endpoint) MNQSYGR (c endpoint)
Weight of the molecular = 854.92
Load = 2
[tex]\to \frac{mass}{Load}[/tex] = 427.46
(n endpoint)RLVSR (c endpoint)
Weight of the molecular = 629.76
Load = 3
[tex]\to \frac{mass}{Load}[/tex]= 209.92
(n endpoint) AATAMASLIK (c endpoint)
Weight of the molecular = 976.20
Load at pH(2). = 2
[tex]\to \frac{mass}{Load}[/tex]= 442.50
(n endpoint) IFAWWY (c endpoint)
Weight of the molecular = 885.03
Load= 1
[tex]\to \frac{mass}{Load}[/tex]= 885.03
It is apparent that RLVSR is the smallest mass ration for this peptide that is detected in the first place.