Answer:
The probability that they will teach different courses is [tex]\frac{2}{3}[/tex].
Step-by-step explanation:
Sample space is a set of all possible outcomes of an experiment.
In this case we will write the sample space in the form (x, y).
Here x represents the course taught by the first part-time instructor and y represents the course taught by the second part-time instructor.
Denote every course by their first letter.
The sample space is as follows:
S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}
The outcomes where the the instructors will teach different courses are:
s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}
The probability of an events E is the ratio of the number of favorable outcomes to the total number of outcomes.
[tex]P(E)=\frac{n(E)}{N}[/tex]
Compute the probability that they will teach different courses as follows:
[tex]P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}[/tex]
Thus, the probability that they will teach different courses is [tex]\frac{2}{3}[/tex].