Answer:
hello some parts of your question is missing below is the complete question
Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.25 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 36
.a. Find the mean and the standard deviation for the numbers of peas with green pods in the groups of 36
The value of the mean is
μ=___ peas.
The value of the standard deviation is
σ=___peas.
b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.
Values of ___ peas or fewer are significantly low.
Values of ___ peas or greater are significantly high.
c. Is a result of 2 peas with green pods a result that is significantly low? Why or why not?
The result (is, is not) significantly low, because 2 peas with green pods is (greater than, equal to, less than) peas.
Answer : A) mean : 9, std = 2.6
B) significantly low value : = 3.8, significantly high value = 14.2
C ) From the significant low value it can be observed that the result is very low because 2 peas with green pods < 3.8 peas with green pods
Step-by-step explanation:
given data :
probability ( p )= 0.25
number of groups ( n )= 36
A ) i) Mean of the of the peas ( u )
u = np = 36 * 0.25 = 9
ii) standard deviation of the peas ( б ) = [tex]\sqrt{np(1-p)} = \sqrt{9(1-0.25)}[/tex] = 2.60
B) Using the range rule of thumb to find the values separating results that are significantly low or significantly high.
note : assuming z = 2 and error = 5%
i) The values that are significantly lower
u - zб = 9 - (2*2.6 )
= 3.8
ii) The values that are significantly higher
u + zб = 9 + (2*2.6)
= 14.2
C ) From the significant low value it can be observed that the result is very low because 2 peas with green pods < 3.8 peas with green pods
