Brain cells, which depend on glucose for energy, use the glucose transporter GLUT3, which has a Km of 1.5mM. Liver cells, which store glucose (as glycogen) after a meal and release glucose between meals, use the glucose transporter GLUT2, which has a Km of 15mM. Calculate the rate (as a % of Vmax) of glucose uptake in brain cells and in liver cells at circulated glucose concentrations of 3mM (starvation), 5 mM (normal levels), and 7mM (after a carbohydrate-rich meal). Use this rearranged M-M equation.

Respuesta :

Answer:

Explanation:

Given that:

The brain cell which uses glucose transporter GLUT3 Km = 1.5 mM

The liver cell which stores glucose GLUT2 Km = 15 mM

The objective is to calculate the rate (as % of Vmax) of glucose uptake in brain cells and liver cells under starvation conditions.

Using the M-M equation i.e Michaelis- Menten equation;

[tex]Rate = \dfrac{V_{max}* [S]}{[S]+K_m}[/tex]

By rearrangement

[tex]\dfrac{Rate}{V_{max}}= \dfrac{[S]}{[S]+K_m}[/tex]

where;

[tex]V_{max}[/tex] = maximum velocity of a reaction

Thus; the rate as a % of Vmax of glucose uptake in brain cells is calculated as:

[tex]\dfrac{Rate}{V_{max}}= \dfrac{[3 \ mM]}{[3 \ mM]+1.5 \ mM}[/tex]

[tex]\dfrac{Rate}{V_{max}}= \dfrac{3 \ mM}{4.5 \ mM}[/tex]

[tex]\dfrac{Rate}{V_{max}}=0.667[/tex]

[tex]\dfrac{Rate}{V_{max}}=66.7 \%[/tex]

the rate as a % of Vmax of glucose uptake in liver cells is calculated as:

[tex]\dfrac{Rate}{V_{max}}= \dfrac{[3 \ mM]}{[3 \ mM]+15 \ mM}[/tex]

[tex]\dfrac{Rate}{V_{max}}= \dfrac{3 \ mM}{18 \ mM}[/tex]

[tex]\dfrac{Rate}{V_{max}}=0.166[/tex]

[tex]\dfrac{Rate}{V_{max}}=17 \%[/tex]

Thus, the uptake is larger brain cells due to the fact that the brain cells GLUT3 have higher tendency to attract glucose.