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A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

A rocket is launched from a tower The height of the rocket y in feet is related to the time after launch x in seconds by the given equation Using this equation class=

Respuesta :

Answer:

10.17 seconds

Step-by-step explanation:

Steps:

1) substitute y=0 into the equation

0=-16x^2+153x+98

2) use the quadratic formula

a= -16

b= 153

c= 98

x= -153 +/- square root of 153^2-4(-16)(98) DIVIDED by 2(-16)

^^ just plug those numbers into the quadratic formula.

x1= 10.17

x2= -0.60

since we cannot have a negative time (-0.60) the answer has to be 10.17

Answer:

9.72 seconds

Step-by-step explanation:

9.72 seconds ( approx )

Step-by-step explanation:

Since, the equation that shows the height of the rocket from the ground,

Where,

x = time after launch, in seconds,

When the rocket hits the ground,

y = 0,

i.e.

By the quadratic formula,

∵ Time can not be negative,

So, the time taken to hit the ground = 9.716 seconds ≈ 9.72 seconds.

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