A basketball player stands near the middle of the court and throws the ball toward the basket.
The path of the ball is a parabola. The ball leaves the player's hands at a height of 6 feet above the ground. The
ball travels to a maximum height of 12 feet when it is a horizontal distance of 18 feet from the player's hands.
Write a function to represent the height of the ball in terms of its distance from the player's hands?

Respuesta :

Answer:

A function to represent the height of the ball in terms of its distance from the player's hands is [tex]y=\frac{-1}{54}(x-18)^2+12[/tex]

Step-by-step explanation:

General equation of parabola in vertex form [tex]y= a(x-h)^2+k[/tex]

y represents the height

x represents horizontal distance

(h,k) is the coordinates of vertex of parabola

We are given that The  ball travels to a maximum height of 12 feet when it is a horizontal distance of 18 feet from the player's hands.

So,(h,k)=(18,12)

Substitute the value in equation

[tex]y=a(x-18)^2+12[/tex]  ---1

The ball leaves the player's hands at a height of 6 feet above the ground and the distance at this time is 0

So, y = 6

So,[tex]6=a(0-18)^2+12[/tex]

6=324a+12

-6=324a

[tex]\frac{-6}{324}=a[/tex]

[tex]\frac{-1}{54}=a[/tex]

Substitute the value in 1

So,[tex]y=\frac{-1}{54}(x-18)^2+12[/tex]

Hence a function to represent the height of the ball in terms of its distance from the player's hands is [tex]y=\frac{-1}{54}(x-18)^2+12[/tex]