Jane is asked to buy some chickens, dogs and ducks for her farm. The total number of animals she needs to buy is 50. She has a budget of $1500 to spend on $20/chicken, $50/dog, and $30/duck. Additionally, the number of chickens should be equal to that of ducks. Create a system of 3 equations to model the situation. Assume the number of chickens is x, dogs is y and ducks is z.

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Answer:

[tex]x + y + z = 50[/tex]

[tex]20x +50 y +30 z = 1500[/tex]

[tex]x = z[/tex]

Step-by-step explanation:

Given

[tex]Chicken = c[/tex]

[tex]Dog = y[/tex]

[tex]Duck = z[/tex]

Since, she wants to buy 50 in total; This can be modeled by:

[tex]x + y + z = 50[/tex]

Considering the budget, we have:

[tex]20x +50 y +30 z = 1500[/tex]

Lastly, we have that

[tex]x = z[/tex]

i.e. Chicken = ducks

There are 20 chickens, 10 dogs and 20 ducks.

Let x represent the number of chickens, y represent the number of dogs and z represent the number of ducks.

The total number of animals she needs to buy is 50. Hence:

x + y + z = 50     (1)

She has a budget of $1500 to spend, hence:

20x + 50y + 30z = 1500   (2)

The number of chickens should be equal to that of ducks. Hence:

x = z

x - z = 0     (3)

Hence, x = 20, y = 10 and z = 20

There are 20 chickens, 10 dogs and 20 ducks.

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