What is the slope of a line perpendicular to the line whose equation is
15x + 12y = -144. Fully reduce your answer.

Respuesta :

Step-by-step explanation:

Hey there!

Let the unknown slope be M2.

The given equation is;

15x + 12y = -144

From equation;

[tex]slope( m) = \frac{ - coeff. \: of \: x}{coeff. \: of \: y} [/tex]

[tex]m = \frac{ - 15}{12} [/tex]

[tex]m = \frac{ - 5}{4} [/tex]

For the condition of perpendicular lines;

[tex]m \times m2 = - 1[/tex]

[tex] \frac{ - 5}{4} \times m2 = - 1[/tex]

[tex] - 5m2 = - 4[/tex]

[tex]m2 = \frac{ - 4}{ - 5} [/tex]

Therefore, the slope is 4/5.

Hope it helps....